Question

A solution contains 10.6 g of glucose. How many moles of glucose are present? How many molecules of glucose are present? How many carbon atoms are there within the glucose molecules

Answer 1

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`moles=0.0588mol\ Glucose`

-
`molecules=3.54x10^(22) molecules \ Glucose`

-
`atoms \ C=2.13x10^(23)atoms \ C`

Step-by-step explanation:

Hello,

In this case, by knowing molar mass of glucose is 180.156 g/mol, we can apply the following mole-mass-particles relationships in order to compute the moles, molecules and carbon atoms in the 10.6-g sample of glucose:

- Moles:

`moles=10.6g\ Glucose*(1mol\ Glucose)/(180.156g\ Glucose)\\\\moles=0.0588mol\ Glucose`

- Molecules: we also use Avogadro's number.

`molecules=10.6g\ Glucose*(1mol\ Glucose)/(180.156g\ Glucose)*(6.022x10^(23) molecules \ Glucose)/(1mol\ Glucose) \\\\molecules=3.54x10^(22) molecules \ Glucose`

- Carbon atoms: here, particularly, one mole of glucose has six moles of carbon atoms, thus:

`atoms\ C=10.6g\ Glucose*(1mol\ Glucose)/(180.156g\ Glucose)*(6molC)/(1mol\ Glucose) *(6.022x10^(23)atoms \ C)/(1molC) \\\\atoms \ C=2.13x10^(23)atoms \ C`

Regards.