Question

What is an equation of the line that passes through the point

(6,−2) and is perpendicular to the line
6x+y=2?

Answer 1

y = 1/6x - 3

Explanation:

Step 1: Find the slope

Take the negative reciprocal of the other slope

m = 1/6

y = 1/6x + b

Step 2: Find b

-2 = 1/6(6) + b

-2 = 1 + b

b = -3

Step 3: Rewrite perpendicular linear equation

y = 1/6x - 3