Question

A plastic box has an initial volume of 2.00 m 3 . It is then submerged below the surface of a liquid and its volume decreases to 1.96 m 3. what is the volume strain on the box

Answer 1

The volume strain on a submerged plastic box with an initial volume of 2.00 m³ and a decreased volume of 1.96 m³ once submerged is 0.02, or 2%.

Step-by-step explanation:

The student is asking about volume strain, which is a concept in physics related to deformation of materials under stress. Volume strain is defined as the fractional change in volume of an object when a pressure is applied to it. In this case, the plastic box experiences a decrease in volume when submerged in a liquid.

To calculate the volume strain on the box, the formula we use is:

Volume Strain = (Change in Volume) / (Original Volume)

Given that the initial volume is 2.00 m³ and the final volume is 1.96 m³, we can calculate the volume strain as follows:

Volume Strain = (2.00 m³ - 1.96 m³) / 2.00 m³

Volume Strain = 0.04 m³ / 2.00 m³

Volume Strain = 0.02 or 2%

This result represents the volume strain imposed on the plastic box when submerged.

Answer 2

Volume strain is 0.02

Step-by-step explanation:

Volume strain is defined as the change in volume to the original volume.

It is given that,

Initial volume of the plastic box is 2 m³

It is then submerged below the surface of a liquid and its volume decreases to 1.96 m³

We need to find the volume strain on the box. It is defined as the change in volume divided by the original volume. So,

`\delta V=(V_f-V_i)/(V_i)\\\\\delta V=(1.96-2)/(2)\\\\\delta V=0.02`

So, the volume strain on the box is 0.02.