197k views
25 votes

\huge{\green}\fcolorbox{blue}{cyan}{\bf{\underline{\red{\color{red} Question}}}}


\mathfrak \orange{ Refer \: To \: Attachment}


\huge{\green}\fcolorbox{blue}{cyan}{\bf{\underline{\red{\color{red} Question}}}} \mathfrak-example-1
User Godbyk
by
5.6k points

1 Answer

5 votes


\qquad\qquad\huge\underline{{\sf Answer}}

Let's find out the gradient (Slope " m ") of line q ;


\qquad \sf  \dashrightarrow \:m = (y_2 - y_1)/(x_2 - x_1)


\qquad \sf  \dashrightarrow \:m = (4 - 0)/(0 - 1)


\qquad \sf  \dashrightarrow \:m = - 4

Now, since we already know the gradient let's find of the equation of line by using its Slope and one of the points using point slope form of line :


\qquad \sf  \dashrightarrow \:y - 4 = m(x - 0)


\qquad \sf  \dashrightarrow \:y = mx + 4

Now, plug in the value of gradient ~


\qquad \sf  \dashrightarrow \:y = - 4x + 4

here we can clearly observe that, the Area under the curve can easily be represented as :


\qquad \sf&nbsp; \dashrightarrow \:y < - 4x + 4

Since, all the values of y that lies in the shaded region is smaller than the actual value of y for the corresponding values of x in the equation of line q

User Chetan Laddha
by
6.8k points