Question

PLEASE ANSWER solve x^(2)+5x+6=0

Answer 1

use the quadratic formula -b+(square root)b^2-4ac / 2a
a=1, b=5, c=6
-5+(square root)5^2-4(1)(6) / 2(1)
x=-2, x=-3

Answer 2

x = -2 OR x = -3

Explanation:

=>
`x^2+5x+6 = 0`

Using mid-term break formula

=>
`x^2+2x+3x+6 = 0`

=> x(x+2)+3(x+2) = 0

Taking x+2 common

=> (x+2)(x+3) = 0

So Either,

x+2 = 0 OR x+3 = 0

x = -2 OR x = -3