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Two waves have amplitudes of 10 m and 7 m, respectively. What are the maximum and minimum amplitudes of the resultant wave if they interfere first constructively, and then destructively?.

User Sulayman
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2 Answers

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Final answer:

Constructive interference: Maximum amplitude = 17 m. Destructive interference: Minimum amplitude = 3 m.

Step-by-step explanation:

In constructive interference, when two waves meet, the amplitudes of the waves add up, resulting in a larger amplitude for the resultant wave.

So, in this case, when two waves with amplitudes of 10 m and 7 m interfere constructively, the maximum amplitude of the resultant wave would be the sum of the two amplitudes, which is 10 m + 7 m = 17 m.

In destructive interference, when two waves meet, the amplitudes can cancel each other out to some extent, resulting in a smaller amplitude for the resultant wave.

So, when the same two waves interfere destructively, the minimum amplitude of the resultant wave would be the difference between the two amplitudes, which is 10 m - 7 m = 3 m.

User Dakin
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I hope this helps you....

Two waves have amplitudes of 10 m and 7 m, respectively. What are the maximum and-example-1
User Ted Wrigley
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