Answer:
The answer is 41%.
Explanation:
First, you have to find the total volume of the cylindrical flask using the formula. Then, you have to substitute the following values into the formula :
![v = \pi * {r}^(2) * h](https://img.qammunity.org/2021/formulas/mathematics/college/cxzge4efajn3r7eooknanxlvk7905enc6x.png)
![let \: \pi = 3.14 \\ let \: r = 3 \\ let \: h = 12](https://img.qammunity.org/2021/formulas/mathematics/college/s33fv2h8z34ov88jgz78e4mekfww4okezt.png)
![v = 3.14 * {3}^(2) * 12](https://img.qammunity.org/2021/formulas/mathematics/college/va93invvuqo03s2m7tqs9x6m89bz605gxn.png)
![v = 3.14 * 108](https://img.qammunity.org/2021/formulas/mathematics/college/xcahdpcbwgh6d2ejhv4s6qbxaoaqpgqdh4.png)
![v = 339.12 {cm}^(3)](https://img.qammunity.org/2021/formulas/mathematics/college/bxtf75cludlt0al6emaifgywus323yu5yl.png)
Next, given that 200cm³ of liquid is poured into the cylinder. So in order to find the volume of flask that is not filled by liquid, you have to subtract :
![v = 339.12 - 200 = 139.12 {cm}^(3)](https://img.qammunity.org/2021/formulas/mathematics/college/w7i1tkw7lfbpkx7ll19ngr1e7dsnhsfnkh.png)
Lastly, you have to find the percentage :
![(139.12)/(339.12) * 100 = 41\% \: (near. \: whole \: number)](https://img.qammunity.org/2021/formulas/mathematics/college/746bv84493f5eafp8dtjeexbwdg2vnz6qn.png)