Question

4.15 Calculate the composition, in weight percent, of an alloy that contains 218.0 kg titanium, 14.6 kg of aluminum, and 9.7 kg of vanadium.

Answer 1

The composition of the allow, in weigh percent, is 89.971 % Titanium, 6.026 % Aluminium and 4.003 % Vanadium.

Step-by-step explanation:

The weight percentage of a element in an allow is equal to the mass of the element divided by the total mass of the allow and multiplied by 100. Then:

Titanium (Ti)

`\% m_(Ti) = (m_(Ti))/(m_(Ti)+m_(Al)+m_(V))* 100\,\%`

`\%m_(Ti) = (218\,kg)/(218\,kg+14.6\,kg+9.7\,kg)* 100\,\%`

`\%m_(Ti) = 89.971\,\%`

Aluminium (Al)

`\% m_(Al) = (m_(Al))/(m_(Ti)+m_(Al)+m_(V))* 100\,\%`

`\%m_(Al) = (14.6\,kg)/(218\,kg+14.6\,kg+9.7\,kg)* 100\,\%`

`\%m_(Al) = 6.026\,\%`

Vanadium (V)

`\% m_(V) = (m_(V))/(m_(Ti)+m_(Al)+m_(V))* 100\,\%`

`\%m_(V) = (9.7\,kg)/(218\,kg+14.6\,kg+9.7\,kg)* 100\,\%`

`\%m_(Al) = 4.003\,\%`

The composition of the allow, in weigh percent, is 89.971 % Titanium, 6.026 % Aluminium and 4.003 % Vanadium.