Question

what is the molarity of a solution that contains 49.8 grams of nai and is dissolved in enough water to make 1.50 liters

Answer 1

Answer: The molarity of solution is 0.221 M

Step-by-step explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

`Molarity=(n)/(V_s)`

where,

n = moles of solute

`V_s` = volume of solution in L

moles of
`NaI` =
`\frac{\text {given mass}}{\text {Molar mass}}=(49.8g)/(149.89g/mol)=0.332mol`

Now put all the given values in the formula of molality, we get

`Molarity=(0.332mol)/(1.50L)`

`Molarity=0.221mol/L`

Therefore, the molarity of solution is 0.221 M