Answer:
-310J
Step-by-step explanation:
The change in internal energy (ΔE) of a system is the sum of the heat (Q) and work (W) done on or by the system. i.e
ΔE = Q + W ----------------------(i)
If heat is released by the system, Q is negative. Else it is positive.
If work is done on the system, W is positive. Else it is negative.
In this case, the system is the balloon and;
Q = -0.659kJ = -695J [Q is negative because heat is removed from the system(balloon)]
W = +385J [W is positive because work is done on the system (balloon)]
Substitute these values into equation (i) as follows;
ΔE = -695 + 385
ΔE = -310J
Therefore, the change in internal energy is -310J
PS: The negative value indicates that the system(balloon) has lost energy to its surrounding, thereby making the process exothermic.