Answer:
The radius of orbit will decrease by 1/4, the satellite will come closer to Earth
Step-by-step explanation:
The orbital speed of any body revolving in an orbit around another boyd is given by:
v (orbital) = √(G · M(central body)/R)
Where G is the gravitation constant.
If the body, e.g satellite is moving around the Earth, then the mass of central body M will also be a constant. Therefore, the only thing on which the orbital velocity will depend on will be Radius of the orbit R.
v ∝ 1/√R
√R ∝ 1/v
Take square:
R ∝ 1/v²
If the velocity of satellite will doubles, then:
R' ∝ 1/ (2v)²
R' ∝ 1/4v²
R' ∝ (1/4)(1/v²)
R' ∝ (1/4)(R)
The radius of orbit will decrease by 1/4, the satellite will come closer to Earth