Question

What mass of CO2 in g will form when 8.94 g

Answer 1

B 6.15g.

Step-by-step explanation:

As per the chemical equation, the reaction ratio between O2 and CO^2 is 2:1, which indicates there is 1 mole of CO^2 produced for every 2 moles of O2 responded.

Now we have to apply the molar mass and mass of O^2 to determine the moles of O^2 i.e

As we know that

`moles\ of\ O^2 = (mass\ of\ O^2)/(molar\ mass\ of\ O^2)`

`= (8.94g)/(32.00g/mol)`

= 0.2794 mole.

So, the moles of CO2 that produced is

`= (0.2794\ moles)/(2)`

= 0.1397 mole

Now we have to apply the moles and molar mass CO^2 to find out the mass of CO^2 which is shown below:

As we know that

`Mass\ of\ CO^2 = moles\ of\ CO^2 * molar\ mass\ of\ CO^2`

`= 0.1397 mole * .44.01g/mole`

= 6.15 g