Answer:
Gina has 29 nickels and 72 dimes.
Explanation:
Each nickel is $0.05, and each dime is $0.10.
If she has 101 total coins, we have:
![nickel + dime = 101](https://img.qammunity.org/2021/formulas/mathematics/college/6p1hoq8rfw96zani6gs2pnh80z3ks1wi9r.png)
All coins worth $8.65, so we have:
![0.05nickel + 0.1 dime = 8.65](https://img.qammunity.org/2021/formulas/mathematics/college/fx0m0f9n9ijv1vb35vyq3prg4p0pu2czxl.png)
Multiplying the second equation by 20, and subtracting the result by the first equation, we have:
![20(0.05nickel + 0.1 dime) - nickel - dime = 20*8.65 - 101](https://img.qammunity.org/2021/formulas/mathematics/college/frvxrifh4wx87z32hupwm24w833mn3iky8.png)
![1nickel +2 dime - nickel - dime = 173 - 101](https://img.qammunity.org/2021/formulas/mathematics/college/wk20a6qqmlfgc4lxt14v1it53wwb6d1fwu.png)
![dime = 72](https://img.qammunity.org/2021/formulas/mathematics/college/2tmncmft9dk3qcicg35t4pla0nn2y62ju7.png)
Then, finding the number of nickels, we have:
![nickel + 72 = 101](https://img.qammunity.org/2021/formulas/mathematics/college/o1kjwac6agnsjiyy46ukhufiq1eh4jfb4a.png)
![nickel = 29](https://img.qammunity.org/2021/formulas/mathematics/college/qdp9ysx6d00awuzqk8oaoz17atj1ugwd4t.png)
So Gina has 29 nickels and 72 dimes.