Question

Abe is going to plant 54 oak trees and 27 pine trees.

Abe would like to plant the trees in rows that all have the same number of trees and are made up of only
one type of tree.
What is the greatest number of trees Abe can have in each row?

Answer 1

Answer: 27 trees

Explanation:

in order to know how many trees Abe can have in each row, we need a number that is a factor of 54 and 27, so that trees ans the 27 pin e trees can be divided up into equal rows.

So, if each row had 9 trees, there would be 54 ÷ 9 = 6 rows of oak trees and 27 ÷ 9 = 3 rows of pine trees. This creates equal rows, but it isn't greatest common factoe of 54 and 27.

To do so, let's find factors 54 and 27

54: 1, 2, 3, 6, 9, 18, 27, 54,

27: 1, 3, 9, 27,

The greatest common factor of 54 and 27 is 27. In math natation this looks like:

gcf (54, 27) = 27

the greatest number of trees that Abe can have in each row is 27

Answer 2

27 trees

Explanation:

Both numbers are divisible by 27. For the oak trees there would be 2 rows and for the pine trees there would be 1 row, each made up of 27 trees.