Question

The displacement, d, in millimeters of a tuning fork as a function of time, t, in seconds can be modeled with the equation d = 0.6 sine (3520 pi t). What is the frequency of the tuning fork?

Answer 1

its C. 1760 Hz

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Answer 2

The frequency of the tuning fork is 1760 Hz.

Explanation:

Suppose we have a sine function in the following format:

`y = Asin(Bx + C)`

The period is:

`T = (2\pi)/(B){/tex]</p><p>The frequency, in Hz, is:</p><p>[tex]F = (1)/(T)`

In this question:

`d = 0.6sin(3520\pi t)`

So

`B = 3520\pi, T = (2\pi)/(3520) = (2)/(3520), F = (1)/(T) = (1)/((2)/(3520)) = (3520)/(2) = 1760`

The frequency of the tuning fork is 1760 Hz.