Question

Given the thermochemical expression

BaO (s) + CO2 (g) =
BaCO3(s)
AH° = -662.8 kJ
Write the thermochemical expression for the production of 4 mol CO2 by decomposition of solid
barium carbonate.

Answer 1

`4BaCO_3(s)\rightarrow 4BaO(s)+4CO_2(g)\ \ \ ;\ \ \ \Delta H=2651.2kJ`

Step-by-step explanation:

Hello,

In this case, in order to answer to the requirement, we first should invert the given reaction since it is the formation of barium carbonate and we need its decomposition:

`BaCO_3(s)\rightarrow BaO(s)+CO_2(g)`

Thereby, the enthalpy of reaction is inverted, to positive since it is the contrary reaction:

`\Delta H=662.8kJ`

Nevertheless, we need to specify it for the formation of 4 moles of carbon dioxide it means:

`4BaCO_3(s)\rightarrow 4BaO(s)+4CO_2(g)\\\Delta H=662.8kJ*4`

Which finally results in the following thermochemical expression:

`4BaCO_3(s)\rightarrow 4BaO(s)+4CO_2(g)\ \ \ ;\ \ \ \Delta H=2651.2kJ`

Regards.