Answer:

Explanation:
Circle is centred at (0, -2)
-> h = 0 & k = - 2
radius of the circle (r) = y-coordinate of the center = - 2
Equation of circle in standard form is given as:

Plugging the values of h, k and r in the above equation, we find:
![(x-0)^2 +[y-(-2)]^2 = (-2)^2](https://img.qammunity.org/2023/formulas/mathematics/college/655iijwk7tqzxtc1d2wm9qqagb9y7wb12a.png)

This is the required equation of circle.