Answer:
2.56 hr
or 2 hr 33 min.
Explanation:
At time zero, Tommy sets off and after t seconds he arrives at A.
At time zero + 2 hrs, Zach sets off and he arrives at B at the same time as Tommy reaches A.
This means that Zach's travel time must be [t-2] hrs.
We know that distance travelled = Average speed x time taken.
So the distance travelled by Tommy = 3t
and the distance travelled by Zach = 4[t-2].
Now we can apply Pythagoras:
(3t)^2+[4(t−2)]^2=8^2
9t^2+16t2^2−32t−32t+64=64
25t^2=64t
25t=64
t=64/25
=2.56 hr