Question

The temperature of a piece of Metal X with a mass of 95.4g increases from 25.0°C to 48.0°C as the metal absorbs 849 J of heat. What is the specific heat of Metal X?

Answer 1

c = 0.38 J/g °C

Explanation:

We have,

Mass of metal X is 95.4 g

Initial temperature was 25°C and final temperature is 48°C.

The metal absorbs 849 J of heat

The heat absorbed due to change in temperature is given by :

`Q=mc\Delta T\\\\c=(Q)/(m\Delta T)\\\\c=(849)/(95.4* (48-25))\\\\c= 0.38\ J/g^(\circ) C`

So, the specific heat of metal X is 0.38 J/g °C.