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The organization that Jones works for is running for a father son dinner for those employees is invited to attend along with his youngest son. If Jones is known to have two children, what is the condition probability that they are both boys given that he is invited to the dinner?

2 Answers

5 votes

Final answer:

The probability that Jones has two sons given that he is invited to the father-son dinner is 1/4 or 0.25.

Step-by-step explanation:

The question asks for the conditional probability that Jones has two sons given that he is invited to the father-son dinner. To calculate this probability, we need to use the concept of conditional probability. Let's assume that the probability of having a boy or a girl is 1/2 each for each child. Since we know that Jones has two children and one of them is a son (since he is invited to the dinner), we can create a sample space of possible outcomes. There are four possible outcomes: BB, BG, GB, and GG, where the letters represent the gender of his two children. Out of these four outcomes, only one outcome (BB) satisfies the condition that both children are boys. Therefore, the probability that Jones has two sons given that he is invited to the dinner is 1/4 or 0.25.

User BWHazel
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3 votes

Answer:

25%

Step-by-step explanation:

The probability of having a boy is 50%

To calculate the probability of him having 2 boys, multiply the probabilities together

0.5(0.5) = 0.25

User Cpiock
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6.9k points