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Solve for x Write both solutions, seperated by a comma 4x^2+5x+1=0

1 Answer

3 votes

Answer:

-1/4 , -1

Explanation:

I solved it using Factorization method and Quadratic Equation .

Factorization Method


4x^2+5x+1=0\\Write +5x- as- a -difference(write+5x-using- two- numbers -in-which-their-sum-is ; 5-and-their-product-is ; 4)\\4x^(2) +4x+1x+1=0\\Factorize-out-common-terms\\4x(x+1)+1(x+1)=0\\Factor-out-(x+1)\\(4x+1)(x+1)=0\\4x+1 =0 \\x+1=0\\4x=0-1\\x =0-1\\4x =-1\\x =-1\\4x=-(1)/(4) \\\\Answer = -1/4 , -1

Quadratic Equation


4x^2+5x+1=0\\a = 4\\b =5\\c = 1\\\\x =(-b\±√(b^2 -4ac) )/(2a) \\\\x = (-(5)\±√((5)^2-4(4)(1)) )/(2(4)) \\\\x = (-5\±√(25-16) )/(8) \\\\x = (-5\±√(9) )/(8) \\\\x = (-5\±3)/(8) \\\\x =(-5+3)/(8) \\\\x = (-5-3)/(8) \\\\x = (-2)/(8) \\\\x = (-8)/(8) \\\\x = -(1)/(4) \\x=-1

User JP Alioto
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