Answer:
For this problem we need to take in count that in elections the parameter of interest is a proportion and the margin of error for this parameter is given by:
![ME = z_(\alpha/2) \sqrt{(\hat p(1-\hat p))/(n)}](https://img.qammunity.org/2021/formulas/mathematics/college/9i6dopbqxeonnr5t492570h55aopibfzdx.png)
And we need to take in count that if the margin of error increase the lenght of the confidence interval increase and otherwise decrease.
For this problem if we increase the sample size n then the denominator for the margin of error would decrease and the resultant effect would be:
A larger sample size gives a narrower confidence interval.
Explanation:
For this problem we need to take in count that in elections the parameter of interest is a proportion and the margin of error for this parameter is given by:
![ME = z_(\alpha/2) \sqrt{(\hat p(1-\hat p))/(n)}](https://img.qammunity.org/2021/formulas/mathematics/college/9i6dopbqxeonnr5t492570h55aopibfzdx.png)
And we need to take in count that if the margin of error increase the lenght of the confidence interval increase and otherwise decrease.
For this problem if we increase the sample size n then the denominator for the margin of error would decrease and the resultant effect would be:
A larger sample size gives a narrower confidence interval.