Answer:

Explanation:
hello

so to know the maximum to y we can check the maximum of
f(x)=

f is derivable and f'(x)=6-2x
f'(x)=0 <=> x = 3
so the maximum is reached for x = 3
f(3)=18-9=9
and then

to be rigorous, we can write the variation table of y to show that there is only one maximum
hope this helps