Question

The position of an object moving along the x

axis is given by x(t) = 2t^2+t^3 +1, where x is
in meters and t in seconds. The acceleration of
the object at t = 2 seconds is:

4m/s?​

Answer 1

Answer: 16 meters per second

Step-by-step explanation:

The derivative of the position is the velocity.

The derivative of the velocity is the acceleration.

x(t) = 2t² + t³ + 1

x'(t) = v(t) = 4t + 3t²

x''(t) = v'(t) = a(t) = 4 + 6t

a(2) = 4 + 6(2)

= 4 + 12

= 16