Question

What is an equation of the line that passes through the points (-7, -6) and
(-1,0)?

Answer 1

equation of line:

y = mx+c

1) find the gradient, m

`m = (y2 - y1)/(x2 - x1)`

`m = ( - 6 - 0)/( - 7 - ( - 1))`

`m = 1`

2) find y-intercept, c using coordinate (-1,0)

y = mx + c

0 = 1(-1)+ c

-1 + c = 0

c = 1

the equation of line: y = x + 1