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Find the value of B - A if the graph of Ax + By = 3 passes through the point (-7, 2), and is parallel to the graph x + 3y = -5. Pls help ASAP btw, the answer isn’t -12/19 or 12/19

User Lewen
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1 Answer

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Answer:


B - A = -6

Explanation:

Given

Point: (-7,2)

x + 3y = -5

Required

Find B- - A in Ax + By = 3

To start with; we need to calculate the slope of x + 3y = -5


x + 3y = -5

Subtract x from both sides


x - x + 3y = -5 - x


3y = -5 - x

Divide both sides by 3


(3y)/(3) = -(5)/(3) - (x)/(3)


y = -(5)/(3) - (x)/(3)

The slope of the line is the coefficient of x

Slope =
- (1)/(3)

The question says line Ax + By = 3 is parallel to line x + 3y = -5; This means that they have the same slope of
- (1)/(3)

Having calculated the slope, next is to calculate the equation of the line using the following formula;


m = (y - y_1)/(x - x_1)

Where m is the slope; m =
- (1)/(3);
(x_1, y_1) = (-7,2)

Substitute these values in the formula above; the formula becomes


-(1)/(3) = (y - 2)/(x - -7)


-(1)/(3) = (y - 2)/(x +7)

Cross Multiply


-1(x+7) = 3(y-2)

Open brackets


-x - 7 = 3y - 6

Add x to both sides


x - x - 7 = 3y - 6 + x


-7 = 3y - 6 +x

Add 6 to both sides


-7 + 6 = 3y -6 + 6 + x


-1 = 3y + x

Multipby both sides by -3


-3(-1) = -3(3y + x)


3 = -9y - 3x


-9y - 3x = 3


-3x - 9y = 3

Comparing the above to Ax + By = 3


Ax = -3x\\A = -3


By = -9y\\B = -9


B - A = -9 - (-3)


B - A = -9 + 3


B - A = -6

User Aprian
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