Answer:
The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846
Explanation:
Step(i):-
Let 'S' be the sample space associated with the drawing of a card
n (S) = 52C₁ = 52
Let E₁ be the event of the card drawn being a king
![n( E_(1) ) = 4 _{C_(1) } = 4](https://img.qammunity.org/2021/formulas/mathematics/college/fowwehb1s0sqkfkldphbci9wqqib8lhdg9.png)
Let E₂ be the event of the card drawn being a queen
![n( E_(2) ) = 4 _{C_(1) } = 4](https://img.qammunity.org/2021/formulas/mathematics/college/kkf20obflr8tyksjjisys46msxjgk38n11.png)
But E₁ and E₂ are mutually exclusive events
since E₁ U E₂ is the event of drawing a king or a queen
step(ii):-
The probability of drawing of a king or a queen from a standard deck of playing cards
P( E₁ U E₂ ) = P(E₁) +P(E₂)
![= (4)/(52) + (4)/(52)](https://img.qammunity.org/2021/formulas/mathematics/college/9666k7kuabgnaxjw46xgi6cmh4qa6tve5u.png)
P( E₁ U E₂ ) =
![(8)/(52)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/nys2qutxbk0tlgduwb0uc1mexv9rzqw57t.png)
step(iii):-
The probability of drawing the compliment of a king or a queen from a standard deck of playing cards
![P(E_(1)UE_(2)) ^(-) = 1- P(E_(1) U E_(2) )](https://img.qammunity.org/2021/formulas/mathematics/college/jr8oz3d7jdgwsi6ty9s1b0s2vw70jt8q6l.png)
![P(E_(1)UE_(2)) ^(-) = 1- (8)/(52)](https://img.qammunity.org/2021/formulas/mathematics/college/kk895wmxq87i6zmlhld0ucannl31z55zhw.png)
![P(E_(1)UE_(2)) ^(-) = (52-8)/(52) = (44)/(52) = 0.846](https://img.qammunity.org/2021/formulas/mathematics/college/5dkej5qyhvhph05zb2ep5vllqkohl0w063.png)
Conclusion:-
The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846