Explanation:
2.(a) uniform speed = distance/ time
= ( 9×16) / 9
= 16 m/s
(b) 19-10 = 9s
(c) 16×9 = 144m
(d) rate of change of speed
= (v-u)/ t
= ( 7-16)/ 6
= -3/2 m/s²
3.(a) uniform speed = distance/ time
= ( 12×20 ) / 12
= 20 m/s
(b) 22-10 = 12s
(c) (12×20) + 1/2(20+60)(18)
= 240+720
= 960m
(d) acceleration
= (v-u)/ t
= ( 60-20 ) / 18
= 20/9 m/² or 2.22 m/s²