Question

A gas occupies a certain volume at 27°C. At what temperature will it volume be doubled, assuming that its pressure remains constant?​

Answer 1

327
`^oC`

Step-by-step explanation:

The temperature at which the volume would be doubled is 327
`^oC`.

Using the formula from Charles' law:

V1/T1 = V2/T2, where V1 = initial volume, T1 = initial temperature, V2 = final volume, and T2 = final temperature.

In this case, V2 = 2V1, T1 = 300 K (27 + 273), and T2 is what we are looking for.

Substituting the different entities in the equation:

V1/300 = 2V1/T2

T2 = 300 x 2 = 600K

Hence, T2 = 600 - 273 = 327
`^oC`