Answer:
C) 2094.40
nearest answer.
Explanation:
Since the given region is bounded by y = x, y = 10 and x = 0
⇒ 0 ≤ y ≤ 10
Radius and Height are 'y'
∴ The required volume
= ∫₀¹⁰2π(radius)(height)dy
= ∫₀¹⁰2π (y) (y) dy
= ∫₀¹⁰2π y² dy
= 2π ∫₀¹⁰ y² dy
Integrate y
=
![2\pi [(y^3)/(3)]_0^(10)](https://img.qammunity.org/2021/formulas/mathematics/college/rbzapc9iy2xmn67db7nhau18qr00qw6vvk.png)
=
![2\pi [(10^3)/(3) - 0]](https://img.qammunity.org/2021/formulas/mathematics/college/uxd6f3vam3yf9jg5a4vl3fpjgzapt7aga2.png)
=

where π is 3.142
= 2,094.66