Answer:
the base of the satellite should be positioned at (0,20)
the best model which describes the equation of the satellite is

Step-by-step explanation:
From the information given:
A satellite dish is designed in such a way that it can pick up radio waves coming from the space.
This satellite dish is designed in the shape of a parabola.
Location of the satellite is situated above the ground
Focus of the satellite is 40 ft above the ground
Using the ground as the x - axis
The objective here is to determine where should the base of the satellite be positioned? &
Which equation best describes the equation of the satellite?
Using the ground as the x - axis;
Let say the x- axis start from the origin (0,0)
Then;
The Focus of the satellite which is 40 ft above the ground will be (0,40)
The position of the base of the satellite will be the vertex (h,k) which is at an equidistant position between the ground and the focus.
(h,k) = (0,20)
The model which best describes the equation of the satellite is as follows :
