What is the temperature (in °C) if 12.1 g of N2 in a 1.3 L container has a pressure of 5.8 atm?

Centralcmd asked Oct 16, 2023

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Centralcmd asked Oct 16, 2023

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11 votes

Answer:

T=-166.8 C

Step-by-step explanation:

PM=m/vRT

T=PMV/mR

T=5.8*14*1.3/12.1*0.08206

T=106.3K

=106-273.15=-166.8 C

Yuriy answered Oct 20, 2023

by Yuriy

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