Answer:
a. a= 1.029 ms⁻²
b. S=25.89 m
Step-by-step explanation:
given
initial speed is u = 7.30 m/sec
final speed is v = 0 m/sec
mu_k = 0.105
kinetic frictional force is Fk = mu_k×m×g
mu_k×m×g = m×a
m cancels
mu_k×g = a
deccelaration a = mu_k×g = 0.105×9.8 =1.029 ms⁻²
b) using v²-u² = 2aS
0²-7.3² = -2×1.029×S
53.29=2.058×S
S = 53.29/2.058
S=25.89 m