Answer:
The value of the test statistic is 4.26.
Explanation:
In this case a hypothesis test is performed to determine whether most adults would erase all of their personal information online if they could.
A random sample of n = 453 adults were selected and it was found that 60% of them would erase all of their personal information online if they could.
Assume that the population proportion is, p = 0.50.
A z-test for single proportion would to used to perform the test.
Compute the value of the test statistic as follows:
![z=\frac{\hat p-p}{\sqrt{(p(1-p))/(n)}}](https://img.qammunity.org/2021/formulas/mathematics/college/zmmvtudrvbjytkovtqtc6awhfoewiyyy9h.png)
![=\frac{0.60-0.50}{\sqrt{(0.50(1-0.50))/(453)}}\\\\=(0.10)/(0.0235)\\\\=4.25532\\\\\approx 4.26](https://img.qammunity.org/2021/formulas/mathematics/college/i3fwkkd4aqg5ycut6qfx2rmwq7a5f1qeow.png)
Thus, the value of the test statistic is 4.26.