Answer:
The arrangement with the greatest resistance is the light bulb of option C. 4 W, 4.5 V
Step-by-step explanation:
The equation for electric power is
power P = IV
also, I = V/R,
substituting into the equation, we have
![P = (V^(2) )/(R)](https://img.qammunity.org/2021/formulas/physics/college/dmajh5rg7v8q20n8puauyalhwsgu8uah1r.png)
![R = (V^(2) )/(P)](https://img.qammunity.org/2021/formulas/physics/college/tq9hb9nexecexni7mvolgwmujrn9e64066.png)
a)
= 2.8 Ω
b)
= 1.5 Ω
c)
5.06 Ω
d)
= 4.5 Ω
from the calculations, one can see that the lightbulb with te greates resistance is
C. 4 W, 4.5 V