Complete question:
Hawkins Manufacturing Company produces connecting rods for 4- and 6-cylinder auto-mobile engines using the same production line. The cost required to set up the production line to produce the 4-cylinder connecting rods is $2,000, and the cost required to set up the production line for the 6-cylinder connecting rods is $3,500. Manufacturing costs are $15 for each 4-cylinder connecting rod and $18 for each 6-cylinder connecting rod. There is no production on weekends, so on Friday the line is diassembled and cleaned. On Monday, the line must be set up to run whichever product will be produced that week. Once the line has been set up, the weekly production capacities are 6000 6-cylinder connecting rods and 8000 4-cylinder connecting rods. Letx4 5 the number of 4-cylinder connecting rods produced next week x6 5 the number of 6-cylinder connecting rods produced next week s4 5 1 if the production line is set up to produce the 4-cylinder connecting rods; 0 if otherwise s6 5 1 if the production line is set up to produce the 6-cylinder connecting rods; 0 if otherwise
a) Using the decision variables x4 and s4, write a constraint that sets next week's maximum production of the 4-cylinder connecting rods to either 0 to 8000 units
b) Using the decision variables x6 and s6, write a constraint that sets next week's maximum production of the 4-cylinder connecting rods to either 0 to 6000 units
c) Write a constraint that requires that production be setup for exactly one of the two rods
d) Write the cost function to be minimized
Answer:
a) x₄ ≤ 8000s₄
b) x₆ ≤ 8000s₆
c) s₄ + s₆ = 1
d) MIN 15x₄ + 18x₆ + 2000s₄ + 3500s₆
Step-by-step explanation:
a) The constraint that sets next week's maximum production of the 4-cylinder connecting rods to either 0 to 8000 units, is written as:
x₄ ≤ 8000s₄
b) The constraint that sets next week's maximum production of the 4-cylinder connecting rods to either 0 to 6000 units is written as:
x₆ ≤ 8000s₆
c) The constraint that requires that production be setup for exactly one of the two rods:
Since we have:
x₄ ≤ 8000s₄ ; x₆ ≤ 8000s₆
The constraint that requires that production be setup for exactly one of the two rods will be:
s₄ + s₆ = 1
d) Write the cost function to be minimized:
Since we are to find the cost function to be minimized, we take the function below:
MIN 15x₄ + 18x₆ + 2000s₄ + 3500s₆