Answer:
radiative heat loss substantially increases as the wall temperature declines
Step-by-step explanation:
The body's heat loss due to convection is ...
(2 W/m^2·K)((32 -20)K) = 24 W/m^2
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The body's heat loss due to radiation in the summer is ...
![\epsilon\sigma(T_b^4-T_w^4)\quad\text{where $T_b$ and $T_w$ are body and wall temperatures ($^\circ$K)}\\\\0.90\cdot 5.6703\cdot 10^(-8)(305.15^4-300.15^4)\,\text{W/m$^2$}\\\\\approx 28.3\,\text{W/m$^2$}](https://img.qammunity.org/2021/formulas/engineering/college/2rgufukc89ma6j77oszmzci0t14u9wff2g.png)
The corresponding heat loss in the winter is ...
![0.90\cdot 5.6703\cdot 10^(-8)(305.15^4-287.15^4)\,\text{W/m$^2$}\\\\\approx 95.5\,\text{W/m$^2$}](https://img.qammunity.org/2021/formulas/engineering/college/g2dgwqedsw5jvnv2vco6p7x56lw43r2nje.png)
Then the total of body heat losses to surroundings from convection and radiation are ...
summer: 24 +28.3 = 52.3 . . . W/m^2
winter: 24 +95.5 = 119.5 . . . W/m^2
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It is reasonable that a person would feel chilled in the winter due to the additional radiative loss to the walls in the winter time. Total heat loss is more than doubled as the wall temperature declines.