Answer:
The range of crying times within 68% of the data is (5.9, 8.1).
The range of crying times within 95% of the data is (4.8, 9.2).
The range of crying times within 99.7% of the data is (3.7, 10.3).
Explanation:
According to the Empirical Rule in a normal distribution with mean µ and standard deviation σ, nearly all the data will fall within 3 standard deviations of the mean. The empirical rule can be broken into three parts:
- 68% data falls within 1 standard deviation of the mean. That is P (µ - σ ≤ X ≤ µ + σ) = 0.68.
- 95% data falls within 2 standard deviations of the mean. That is P (µ - 2σ ≤ X ≤ µ + 2σ) = 0.95.
- 99.7% data falls within 3 standard deviations of the mean. That is P (µ - 3σ ≤ X ≤ µ + 3σ) = 0.997.
The mean and standard deviation are:
µ = 7
σ = 1.1
Compute the range of crying times within 68% of the data as follows:
![P(\mu-\sigma\leq X\leq \mu+\sigma)=0.68\\\\P(7-1.1\leq X\leq 7+1.1)=0.68\\\\P(5.9\leq X\leq 8.1)=0.68](https://img.qammunity.org/2021/formulas/mathematics/college/ozhkq9gydgevrpn3rew8cv51vq5gmwfm1i.png)
The range of crying times within 68% of the data is (5.9, 8.1).
Compute the range of crying times within 95% of the data as follows:
![P(\mu-2\sigma\leq X\leq \mu+2\sigma)=0.95\\\\P(7-2.2\leq X\leq 7+2.2)=0.95\\\\P(4.8\leq X\leq 9.2)=0.95](https://img.qammunity.org/2021/formulas/mathematics/college/9gbdd77ivplxp4sk38wh9ff9e8j67hc0rc.png)
The range of crying times within 95% of the data is (4.8, 9.2).
Compute the range of crying times within 99.7% of the data as follows:
![P(\mu-3\sigma\leq X\leq \mu+3\sigma)=0.997\\\\P(7-3.3\leq X\leq 7+3.3)=0.997\\\\P(3.7\leq X\leq 10.3)=0.997](https://img.qammunity.org/2021/formulas/mathematics/college/8kxmwfxf4uw2i4zn142gu8kp0i00cvstcz.png)
The range of crying times within 99.7% of the data is (3.7, 10.3).