Answer:
1/6 × 1/6
The complete question related to this as found on math24seven website is stated below:
Find the errors. Mario and Tabitha are calculating the probability of getting a 4 and then a 2 if they roll a die twice. Who is correct? Explain your reasoning.
Find attached their calculations
Explanation:
We are to determine which of the two calculations given by Mario and Tabitha for getting a probability of 4 and then 2 is correct.
To do this, let's work out the calculations ourselves.
In a die, we have the faces numbered from 1 to 6
Outcome of rolling a die = {1, 2, 3, 4, 5, 6}
If the die is rolled twice, the probability of getting a 4 and then 2 = Pr(4 in the first roll and 2 in the 2nd roll)
Let the probability = Pr(2 and 4)
Probability of getting 2 = Pr(2)
Pr(2) = (number times it occurred)/(total number of outcome)
Pr(2) = 1/6
Probability of getting 4 = Pr(4)
Pr(4) = (number times it occurred)/(total number of outcome)
Pr(4) = 1/6
Pr(2 and 4) = 1/6 × 1/6
Looking at both calculations, only Mario has same answer as derived from the calculation.
Therefore Mario is correct.