Question

What are the degree and zeros of the polynomial f(x)=(x-1)^2(x+1)

Answer 1

Explanation:

• First to khow the degree of this polynomial function we should develop it

(x-1)²(x+1) = x³-2x²+x+x²-2x+1

= x³-x²-x+1

= x²(x-1)-x+1

= x²(x-1)-(x-1)

= (x²-1) (x-1)

• THE DEGREE IS 3 we can deduce it from the second line
• THE ZEROES are -1 and 1 SINCE BOTH MAKE THE EXPRESSION EQUAL 0

Answer 2

degree 3 zeros -1 and 1

Explanation:

This is a third degree polynomial

f(x)=(x-1)^2(x+1)

It has an x^2 from the first term and an x from the second term for x^3

The zeros are x-1 =0 which means x=1

x+1 = 0 x=-1