Question

A baboon steals an apple and runs to a nearby boulder 10.0\,\text m10.0m10, point, 0, start text, m, end text to its left. The baboon reaches the boulder in 1.0\,\text s1.0s1, point, 0, start text, s, end text with a constant acceleration of 20.0\,\dfrac{\text m}{\text s^2}20.0 s 2 m ​ 20, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction leftward. What was the baboon's initial velocity when it started running to the boulder?

Answer 1

Given that,

Distance = 10 m

Time = 1.0 sec

Acceleration a =20 m/s²

We need to calculate the baboon's initial velocity

Using equation of motion

`s=ut+(1)/(2)at^2`

Where, s = distance

t = time

a = acceleration

Put the value in to the formula

`10=u*1+(1)/(2)*20*1^2`

`u=10-10`

`u=0\ m/s`

Hence, The baboon's initial velocity is zero.