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SOMEONE PLEASE HELP!!!!!!!!!

Solve 2 x - 1 < 7 and 5x + 3 < 3.

A. {x l x < 0}
B. {x l x < 4}
C. {x l 0 < x < 4}​

User Ruthie
by
6.5k points

2 Answers

2 votes

Answer:

A. {x l x < 0}

Explanation:

2 x - 1 < 7 and 5x + 3 < 3.

Solve one inequality at a time

2 x - 1 < 7

Add 1 to each side

2 x - 1+1 < 7 +1

2x <8

Divide by 2

2x/2 <8/4

x <4

Now solve the other

5x + 3 < 3

Subtract 3

5x +3-3 < 3-3

5x<0

x <0

Recombine

x<4 and x<0

We go with the more restrictive and merge the overlapping interval since we have an and

x<0

User Marypat
by
5.2k points
1 vote

Answer:

Explanation:

2x - 1 < 7

Add 1 to both sides

2x - 1 + 1 < 7+1

2x < 8

Divide both sides by 2

2x/2 < 8/2

x < 4

5x + 3 < 3

Subtract 3 form both sides

5x + 3 - 3 < 3-3

5x < 0

x < 0

x <4 & x < 0

So, solution ,

{x / x< 0 }

User IaMaCuP
by
5.5k points