Question

Mr. Brown has $185 in his wallet consisting of only $5 bills and $10 bills. If there are 28 bills in his wallet, how many of each type are there?

Answer 1

9 bills of $10 and 19 bills of $5

Explanation:

Mr. Brown has $185 of which he has $10 bills and $5 bills. He has total 28 bills in his wallet all of which can be either $10 bill or $5 bill. The numbers of $10 bills are 9 bills and 19 bills of $5 bills. The total will be 28 bills (9 bills + 19 bills). The total amount will be $185 [(9 bills *$5) + (19 bills of $10)].