Question

A machine lifts up containers of coal from the mine and lowers empty containers down. The machine uses an electric motor connected to a 600 V d.c. supply.The maximum current in the motor is 4000 A. *Calculate the maximum power available from the motor. Give your answer in MW* power = voltage x current i believe

Answer 1

The maximum power available to the motor is 2.4 MW

Explanation:

The power of a circuit that has a current, I, and a voltage, V, is given by the relation

Electrical power, P = I²R = I× I×R = I × V

Therefore given that the parameters are;

Voltage in the d.c. power supply = 600 V d.c.

Maximum current in the motor = 4000 A

Therefore, we can find the power as follows;

Maximum motor power = Voltage × Current

The maximum motor power, P available = 600 V × 4000 A = 2400000 W which on converting to MW becomes;

The maximum power available to the motor , P = 2.4 MW.