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Find two complex numbers whose sum is 12 and whose product is 37.​

User Huczilla
by
8.5k points

1 Answer

2 votes

Answer:

6 ± i and 6 ± i

Explanation:

Let x be the first number.

Let y be the second number.

x + y = 12

x × y = 37

Solve for x in the first equation.

x = 12 - y

Put x as 12-y in the second equation and solve for y.

(12- y)y = 37

12y - y² = 37

- y² + 12y - 37 = 0

y = 6 ± i

Put y as 6 ± i in the first equation and solve for x.

x + 6 ± i = 12

x = 12 - 6 ± i

x = 6 ± i

User Yokto
by
7.9k points

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