Question

Find the wavelength of light given off by a hydrogen atom when its electron drops from the n = 4 to n = 1 energy level

Answer 1

Find energy

`\\ \rm\Rrightarrow E=-13.6\left((1)/(6^2)-(1)/(4^2)\right)`

`\\ \rm\Rrightarrow E=-13.6\left((1)/(36)-(1)/(16)\right)`

`\\ \rm\Rrightarrow E=-13.6(0.0278-0.0625)`

`\\ \rm\Rrightarrow E=-13.6(-0.347)`

`\\ \rm\Rrightarrow E=0.47eV`

Now

`\\ \rm\Rrightarrow E=h\\u`

`\\ \rm\Rrightarrow \\u=(E)/(h)`

`\\ \rm\Rrightarrow \\u=(0.47* 10^(-19))/(6.626* 10^(-34))`

`\\ \rm\Rrightarrow \\u=0.071* 10^(15)`

`\\ \rm\Rrightarrow \\u=7.1* 10^(13)Hz`

Answer 2

Answer: 1.55 x 10 -19J on top

Step-by-step explanation: