Answer:
m<ABC > m<ACB (angle property of a triangle)
Explanation:
Given that: ΔABC
AB = AX
Prove: m<ABC > m<ACB
From the given diagram,
ΔABX is an isosceles triangle (two congruent sides and angles)
<AXB = m<ABX =
(isosceles triangle property)
AC = AX + XC
Thus,
AC > AB
m<ABC = m1 + m3 ≥
m<ACB <
(acute angle property)
Therefore since in a triangle the longest side is opposite to the greatest angle, then;
m<ABC > m<ACB (angle property of a triangle)