Question

What are the chances of choosing a black marker out of a bag containing 3 red markers, 5 blue markers, 3 yellow markers, and 4 black markers? What is the probability of choosing two black markers if the first marker is put back before the second is drawn?

Answer 1

`(16)/(225)`.

Explanation:

It is given that,

Number of red markers = 3

Number of blue markers = 5

Number of yellow markers = 3

Number of black markers = 4

Total markers = 3 + 5 + 3 + 4 = 15

Probability of getting a black marker is

`P(Black)=\frac{\text{Number of black markers}}{\text{Total markers}}`

`P(Black)=(4)/(15)`

Probability of choosing two black markers if the first marker is put back before the second is drawn, is

Required probability
`=P(Black)* P(Black)`

`=(4)/(15)* (4)/(15)`

`=(16)/(225)`

Therefore, the probability of choosing two black markers if the first marker is put back before the second is drawn, is
`(16)/(225)`.