Question

Anyone know how to solve 35 and 39 by chance?

Answer 1

33.
`f^(-1)(7) = 6`

34.
`f^(-1)(2) = 3`

35.
`f(-8) = -4`

36.
`f(-1) = -2`

37.
`f(1) = 0`

38.
`x = 7`

39.
`f^(-1)(0) = 1`

40.
`f^(-1)(3) = 7`

Explanation:

The inverse function
`f^(-1)(x)` points back from f(x) to x, that is, if we have
`f(x) = y`, then we have that
`f^(-1)(y) = x`, and if we have
`f^(-1)(y) = x`, then we have
`f(x) = y`

So we have that:

33.

`f(6) = 7`

`f^(-1)(7) = 6`

34.

`f(3) = 2`

`f^(-1)(2) = 3`

35.

`f^(-1)(-4) = -8`

`f(-8) = -4`

36.

`f^(-1)(-2) = -1`

`f(-1) = -2`

In the exercises from 37 to 40, we do the same above, but now using the values in the table given. So we have:

37.

if
`x = 1`,
`f(1) = 0`

38.

if
`f(x) = 3`,
`x = 7`

39.

We just need to find where f(x) = 0. If
`f(1) = 0`,
`f^(-1)(0) = 1`

40.

We just need to find the value of f(7). If
`f(7) = 3`,
`f^(-1)(3) = 7`