Question

Calcular la magnitud de la fuerza eléctrica entre dos cargas cuyos valores son q1=2 milicoulombs, q2=4 milicoulombs, al estar separadas en el vacío por una distancia de 30 cm

Answer 1

Fe = 7.98*10^5N/C

Step-by-step explanation:

In order to calculate the electric force between the two charges you use the following formula:

`F_e=k(q_1q_2)/(r^2)` (1)

k: Coulomb's constant = 8.98*10^9Nm^2/C^2

q1 = 2mC = 2*10^-3C

q2 = 4mC = 4*10^-3C

r: distance between the charge = 30cm = 0.3m

You replace the values of the parameters in the equation (1):

`F_e=(8.98*10^9Nm^2/C^2)((2*10^(-3)C)(4*10^(-3)C))/((0.3)^2)\\\\F_e=7.98*10^5(N)/(C)`

The force between the charges q1 and q2 is 7.98*10^5N/C